Ruby China

Rails 遍历数组内对象的属性，有什么好的方法？

secondrocker · October 27, 2012 · Last by small_fish__ replied at November 02, 2012 · 7223 hits

tagnames=[] list.tags.each{|t| tagnames.push(t.name) }
tagnames.join(',')

我是这么做的，看着真不舒服... 有什么更简便的，牛 X 的方法木有？

2 likes
hungyuhei #1 October 27, 2012

list.tags.reduce([]) { |arr, t| arr << t.name }.join(',')

gaicitadie #2 October 27, 2012 
list.tags.map{ |t| t.name }.join(',')
vincent #3 October 27, 2012

list.tags.map(&:name).join(',')

Asakawa #4 October 27, 2012

list.tags.collect{|t| t.name}.join(',')

simlegate #5 October 30, 2012

#3 楼 @vincent 这是什么用法？

shawnyu #8 October 30, 2012

#5 楼 @simlegate map 接收一个块参数 &:attribute 相当于｛｜item｜ item.attribute｝

woaigithub #9 November 02, 2012

select map reduce

You need to Sign in before reply, if you don't have an account, please Sign up first.