Ruby China

新手问题 一个关于当前时间所在范围的判断，or 字符串 整型判断

wminjay · January 28, 2013 · Last by chucai replied at January 28, 2013 · 3174 hits

t = Time.now.strftime("%H") if t>9 && t<20 then puts "ok" end

提示： in `>': comparison of String with 9 failed (ArgumentError)

于是修改了一下

t = Integer(Time.now.strftime("%H")) if t>9 && t<20 then puts "ok" end

结果提示 : in `Integer': invalid value for Integer: "09" (ArgumentError)

我蛋疼了，各位有什么好办法吗？ 我的需求是判断时间在 9 点 -20 点之间输出 ok

wminjay #0 January 28, 2013

原来这样就 ok 了 t = Time.now.strftime("%H").to_i if t>9 && t<20 then puts "ok" end

qhwa #1 January 28, 2013 
puts "ok" if (10..19).include? Time.now.hour
2 likes
quakewang #3 January 28, 2013

可以用 Range

p "OK" if (9..20) === Time.now.hour
jjym #4 January 28, 2013

0 开头的会被认为是 8 进制

wminjay #5 January 28, 2013 
p "thanks"
keating #6 January 28, 2013

看来Integer方法和 js 的一样蛋疼

chucai #7 January 28, 2013 
puts "ok" if Time.now.hour.in?(10..19)
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