新手问题这个 JSON 怎么按自身格式嵌套转换字段

lyb124553153 · May 14, 2017 · Last by lyb124553153 replied at May 15, 2017 · 1912 hits

怎么把返回的数据按照某个字段

def index
    json_str = Groupall.to_json
    render :json => json_str, status => '200'
  end

[
  {
    "id": 3,
    "group": "分组0",
    "name": "测试2",
    "active": "ceshi",
    "created_at": "2017-05-02T02:02:37.283Z",
    "updated_at": "2017-05-02T02:02:37.283Z"
  },
  {
    "id": 4,
    "group": "分组1",
    "name": "测试3",
    "active": "ceshi",
    "created_at": "2017-05-02T02:02:37.287Z",
    "updated_at": "2017-05-02T02:02:37.287Z"
  },
  {
    "id": 5,
    "group": "分组0",
    "name": "测试4",
    "active": "ceshi2",
    "created_at": "2017-05-02T02:02:37.290Z",
    "updated_at": "2017-05-02T02:02:37.290Z"
  }
]

想要转换成就是按照 group 字段的值进行分组，然后再 children 里面把 NAME 相同的设为一个对象，把 active，不同的字段合并到一个数组里

[
  {

    "group": "分组0",
    "children":[
     {“name”:"测试2"  ,"active": ["ceshi2"]}，
     {“name”:"测试4"} 
    ]
 },
  {   
    "group": "分组1",
   "children":[
   {“name”:测试3,"active": ["ceshi2"]}
   ]
  },

]