。。。这肯定不是 ruby。。。

arr = [["a:1","b:0"],["c:2","b:0","d:5"]]

hash = {}
arr_size = arr.size

arr.each_with_index do |a, i|
    a.each_with_object({}) do |str, h|
        str =~ /^(.*):(.*)$/
        h[$1] = $2
    end.each do |k, v|
        hash[k] ||= [nil] * arr_size
        hash[k][i] = v
    end
end

p hash

#2 楼 @piecehealth 看似不长的代码，其实很考功力。学习了，谢谢！

#3 楼 @chenge 写复杂了……

arr.each_with_index do |a, i|
    a.each do |str|
        str =~ /^(.*):(.*)$/
        k, v = $1, $2
        hash[k] ||= [nil] * arr_size
        hash[k][i] = v
    end
end

就行

@piecehealth 好用！严重感谢！！！

很变态的数据格式。。。