新手问题 Ruby 分析 XML 文件中 each block 的问题
请问，分析一个 XML 文件 (参看底部)，想汇总成文档成 1 Ruby The Ruby Way 2 Space The Case for Mars
appPathArray.each do |i|
puts i
doc.elements.each("library/section") { |e| puts e.attributes["name"] }
doc.elements.each("library/section") { |e| puts e.elements["title"].text }
end
问题是，上边代码第三四行，如何控制输出第 i 行？类似 doc.elements.each("library/section") { |e| puts e(i).attributes["name"] } 谢谢
The Ruby Way Hal Fulton Second edition. The book you are now reading. Ain't recursion grand? The Case for Mars Robert Zubrin Pushing toward a second home for the human race. First Man: The Life of Neil A. Armstrong James R. Hansen Definitive biography of the first man on the moon.
在命令行测试出的作法：
$ irb -rnokogiri
>> doc = Nokogiri::XML(open('./raw.xml'))
=> ...
>> doc.xpath('//section').each_with_index{|x,i| puts "#{i+1} #{x.attributes['name']} #{x.at('title').text}"}
1 Ruby The Ruby Way
2 Space The Case for Mars
=> ...
第三个没出来，改成这样子：
require "nokogiri"
doc = Nokogiri::XML(open('./raw.txt'))
index = 0
doc.xpath('//section').each do |section|
name = section.attributes['name']
section.search('title').each do |title|
index+=1
puts "#{index} #{name} #{title.text}"
end
end