https://ruby-china.org/UOvOU-github en-us <p>where 函数传递参数可以用</p> <pre class="highlight ruby"><code><span class="no">A</span><span class="p">.</span><span class="nf">where</span><span class="p">(</span><span class="s2">"id = ?"</span><span class="p">,</span> <span class="n">p_id</span><span class="p">)</span> </code></pre> <p>但查阅文档发现 joins, 没有这样的操作 请问如何能达到类似如下的效果</p> <pre class="highlight ruby"><code><span class="no">A</span><span class="p">.</span><span class="nf">joins</span><span class="p">(</span><span class="s2">"LEFT JOIN bs ON as.id = bs.id AND bs.state in (?)"</span><span class="p">,</span> <span class="n">state_arr</span><span class="p">)</span> </code></pre> <p>用 on 的原因是，不想 A 因 B 的条件 而被过滤掉</p> UOvOU-github Fri, 13 Oct 2017 14:47:02 +0800 https://ruby-china.org/topics/34368 https://ruby-china.org/topics/34368