https://ruby-china.org/PeishuaiLee en-us <p>在 java 中：</p> <pre class="highlight java"><code><span class="nc">String</span> <span class="n">classPath</span><span class="o">=</span><span class="s">"path1.path2.path3.path4...className"</span><span class="o">;</span> <span class="nc">Objectp</span><span class="o">[]</span> <span class="n">args</span><span class="o">=</span><span class="k">new</span> <span class="nc">Object</span><span class="o">[</span><span class="k">new</span> <span class="nf">Object</span><span class="o">(),</span><span class="k">new</span> <span class="nc">Object</span><span class="o">()...];</span> <span class="nc">Class</span> <span class="n">clazz</span><span class="o">=</span><span class="nc">Class</span><span class="o">.</span><span class="na">forName</span><span class="o">(</span><span class="n">classPath</span><span class="o">,</span><span class="n">args</span><span class="o">);</span> <span class="nc">Object</span> <span class="n">obj</span><span class="o">=</span><span class="n">clazz</span><span class="o">.</span><span class="na">newInstance</span><span class="o">();</span> <span class="nc">String</span> <span class="n">methodName</span><span class="o">=</span><span class="s">"methodName"</span><span class="o">;</span> <span class="nc">Method</span> <span class="n">method</span><span class="o">=</span><span class="n">clazz</span><span class="o">.</span><span class="na">getMethod</span><span class="o">(</span><span class="n">methodName</span><span class="o">);</span> <span class="nc">Object</span> <span class="n">returnObject</span><span class="o">=</span><span class="n">method</span><span class="o">.</span><span class="na">invoke</span><span class="o">(</span><span class="n">obj</span><span class="o">,</span><span class="n">args</span><span class="o">);</span> </code></pre> <p>请问各位 大牛：在 ruby 中如何实现以上的机制，利用给定的类文件路径以及指定调用的方法名称，类名称与 ruby 文件名称一样</p> PeishuaiLee Sun, 16 Jul 2017 14:50:40 +0800 https://ruby-china.org/topics/33516 https://ruby-china.org/topics/33516