效果应该就像没有那个 anction 一样

route 里面不设置不就好了

继承是is a的关系，也就是说，可以把子类完全当作一个父类来对待，所以子类必然要响应所有父类的action，否则违背继承的逻辑。所以，你可能哪里错了。programing ruby 中的一段话：

Now, a lot of research has been done on type theories. One of the more famous results is
the Liskov Substitution Principle. Formally, this states: “Let q(x) be a property provable
about objects x of type T. Then q(y) should be true for objects y of type S where S is a
subtype of T.” What this means is that you should be able to substitute an object of a child
class wherever you use an object of the parent class—the child should honor the parent’s
contract. There’s another way of looking at this: we should be able to say that the child
object is a kind of the parent. We’re used to saying this in English: a car is a vehicle, a cat
is an animal, and so on. This means that a cat should, at the very least, be capable of doing
everything we say that an animal can do.

#2 楼 @benzhang route 是 resource 的那种

@kikyous 文档里有 http://guides.rubyonrails.org/routing.html#restricting-the-routes-created

我不会继承一个有 action 的类，继承的时候只会继承一些 Base controller，里面定义了一些 filter 和 private 方法。

或者，你重写它，哇嘎嘎